Math, asked by aaditya1794, 1 year ago

the sides of a rectangular park are in the ratio 4:3. If its area is 1728 m square ,find the cost of fencing it as Rs 2.50 per metre.

Answers

Answered by rathibhagwati3
9

Answer:


Step-by-step explanation:

Let, the sides be x.

So, the ratio would be...4x:3x.

Area = l*b


1728 = 4x*3x

1728 = 12x^2

1728/12 = x^2

144 = x^ 2

So, x = 12m (Sqrt of 144)


4x = 4*12 = 48m

3x = 3*12 = 36m

Now, Perimeter = 2 (l+b)

= 2 (48+36)

= 2 (84)

= 168m


Cost of fencing = 168*2.5

= Rs. 420


Answered by Anonymous
13

Answer:

Step-by-step explanation:

Let, the sides be x.

So, the ratio would be...4x:3x.

Area = l*b

1728 = 4x*3x

1728 = 12x^2

1728/12 = x^2

144 = x^ 2

So, x = 12m (Sqrt of 144)

4x = 4*12 = 48m

3x = 3*12 = 36m

Now, Perimeter = 2 (l+b)

= 2 (48+36)

= 2 (84)

= 168m

Cost of fencing = 168*2.5

= Rs. 420

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