Question

The sides of a rectangular park are in the ratio 4:3.if the area is 1728m.sq,find the cost of fencing in at the rate of RS.2.5/m

Answer 1

Answer:

let the sides be 4x and 3x.

Area of Rectangle = length x breadth

then,

4x*3x=1728

12x^2 = 1728

x^2 = 1728/12

x=√144

x= 12

If x is 12 and sides are 4x and 3x then,

4x= 4*12=48

3x=3*12=36

Now,

Fencing is done on boundary so we need to find the perimeter.

perimeter of Rectangle = 2(l+b)

2(48+36)=168

Cost of fencing at the rate of 2.5 m = 168*2.5=RS.420

The answer is RS.420

Answer 2

Answer:

• Total cost of fencing = Rs. 420.

Step-by-step explanation:

Given:

• Sides of rectangle are in ratio 4:3.
• Area of rectangle = 1728 m²
• Cost of fencing = Rs. 2.5/m

To Find:

• Total cost of fencing.

Let sides of rectangle be:

• Length = 4x
• Breadth = 3x

Now, first we will find dimension of park.

⇒ Area of park = l × b

⇒ 1728 = 4x × 3x

⇒ 1728 = 12x²

⇒ x² = 1728/12

⇒ x² = 144

⇒ x = √144

⇒ x = ± 12

We know that, Length cannot be negative.

∴ x = 12 m

So,

• Length = 4x = 12 × 4 = 48 m
• Breadth = 3x = 12 × 3 = 36 m

Now, we will calculate perimeter,

⇒ Perimeter of rectangle = 2(l + b)

⇒ Perimeter of rectangle = 2(48 + 36)

⇒ Perimeter of rectangle = 2(84)

⇒ Perimeter of rectangle = 168 m.

Now, cost of fencing 1 m = Rs. 2.5

So, cost of fencing of 168 m = Rs. 2.5 × 168

                                          = Rs. 420.

Hence, total cost of fencing = Rs. 420.

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