The sides of a rectangular park arein the ratio 4:3 if ite area is 2028sq.m,find the cost of fencing it at 3rs. per metre
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the ratio of sides of the rectangle are 4:3.
let the common ratio be X.
area is 2028^2 m(given)
so,2028^2m=4x×3x...
or,12x
so,X=2028/12
=169
so,4x=169×4.....=676
and,3x=169×3....=507
so,perimeter =2(676+507)
2366m
so,the money required for fencing the park=2366×3 rupees
= 7098 rupees
let the common ratio be X.
area is 2028^2 m(given)
so,2028^2m=4x×3x...
or,12x
so,X=2028/12
=169
so,4x=169×4.....=676
and,3x=169×3....=507
so,perimeter =2(676+507)
2366m
so,the money required for fencing the park=2366×3 rupees
= 7098 rupees
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