Math, asked by pawangupt567gmailcom, 1 year ago

The sides of a rectungular park are in the ratio 3:2 if it's area is 1536 m2 find the cost of fencing it at 23.50 per metre

Answers

Answered by RishavRJ
5
i hope it will help u
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Answered by Anonymous
2
hii!!

here's Ur answer...

given the sides of the rectangular park are in ratio 3:2

let the sides of the rectangular park be 3x and 2x

area of the rectangular park = 1536m²

therefore l × b = 1536m²

==> 3x × 2x = 1536m²

==> 6x² = 1536m²

==> x² = 1536/6

==> x² = 256

==> x = √256

==> x = 16

hence, sides of the rectangular park are :-

length = 3x = 3 × 16 = 48m

breadth = 2x = 2 × 16 = 32m

therefore perimeter of the rectangular park = 2 ( l + b )

= 2 ( 48 + 32 )

= 2 × 80

= 160m

hence, cost of fencing the rectangular park at the rate of ₹23.5 per m = 160 × 23.5 = ₹3760

hope this helps..!!
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