The sides of a rectungular park are in the ratio 3:2 if it's area is 1536 m2 find the cost of fencing it at 23.50 per metre
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hii!!
here's Ur answer...
given the sides of the rectangular park are in ratio 3:2
let the sides of the rectangular park be 3x and 2x
area of the rectangular park = 1536m²
therefore l × b = 1536m²
==> 3x × 2x = 1536m²
==> 6x² = 1536m²
==> x² = 1536/6
==> x² = 256
==> x = √256
==> x = 16
hence, sides of the rectangular park are :-
length = 3x = 3 × 16 = 48m
breadth = 2x = 2 × 16 = 32m
therefore perimeter of the rectangular park = 2 ( l + b )
= 2 ( 48 + 32 )
= 2 × 80
= 160m
hence, cost of fencing the rectangular park at the rate of ₹23.5 per m = 160 × 23.5 = ₹3760
hope this helps..!!
here's Ur answer...
given the sides of the rectangular park are in ratio 3:2
let the sides of the rectangular park be 3x and 2x
area of the rectangular park = 1536m²
therefore l × b = 1536m²
==> 3x × 2x = 1536m²
==> 6x² = 1536m²
==> x² = 1536/6
==> x² = 256
==> x = √256
==> x = 16
hence, sides of the rectangular park are :-
length = 3x = 3 × 16 = 48m
breadth = 2x = 2 × 16 = 32m
therefore perimeter of the rectangular park = 2 ( l + b )
= 2 ( 48 + 32 )
= 2 × 80
= 160m
hence, cost of fencing the rectangular park at the rate of ₹23.5 per m = 160 × 23.5 = ₹3760
hope this helps..!!
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