Question

The sides of a rhombus are 10 cm each and one diagonal is 16 cm, find the area
of the rhombus. pls.. solve it fast.

​

Answer 1

Hello Good evening!!

$\huge \sf{\purple {\underline{AnsweR : }}}$

96 cm²

$\bf\red {\underline{SolutioN : }}$

Given,

Sides of rhombus = 10 cm each.

One diagonal = 16 cm

Using the formula :

$\maltese \: \: \tt \red{A = \frac{P \: \: Q }{2}}$

$\purple \implies \tt \frac{ \sqrt{ {p}^{2} + {q}^{2} } }{2}$

$\purple \implies \tt \: A \: = \frac{1}{2} p \: \sqrt{4 {a}^{2} - {p}^{2} }$

$\purple \implies \tt \: A \: = \: \frac{1}{2} .16 \sqrt{4. {10}^{2} - {16}^{2} } \\ \\ \purple \implies \tt {A \: = \: \frac{1}{\cancel2}}. \cancel{16}_{ \: 8} \: \sqrt{400 - 256} \\ \\ \purple \implies \tt {8 \sqrt{144} }\\ \\ \purple\therefore \: \tt \: 96 {cm}^{2}$

Hope You understood :)

Thank You ❤️☺️

Answer 2

$\huge\mathcal{\fcolorbox{aqua}{azure}{\red{❖Question}}}$

The sides of a rhombus are 10 cm each and one diagonal is 16 cm, find the area

of the rhombus. pls.. solve it fast.

Answer:- hope it helps