Math, asked by mrsinghave5295, 1 year ago

The sides of a rhombus are 5cm long and one of its angle is 100.Compute its area.

Answers

Answered by Rishiksingh
20
area = 1/2 * base * height
a = 1/2 * 5 * 5 * sin80
a = 12.5sin80
Answered by windyyork
13

Answer: Area of the rhombus is 24.58 sq. cm.

Step-by-step explanation:

Since we have given that

Side of a rhombus = 5 cm

Measure of one of its angle = 100°

So, Half of its angle = 50°

So, Measure of first diagonal would be

d_1=2\times 5\times \sin 50^\circ\\\\d_1=7.66\ cm

Measure of second diagonal would be

d_2=2\times 5\times \cos 50^\circ\\\\d_2=6.42\

So, Area of diagonal would be

\dfrac{1}{2}\times d_1\times d_2\\\\=\dfrac{1}{2}\times 7.66\times 6.42\\\\=24.58\ cm^2

Hence, Area of the rhombus is 24.58 sq. cm.

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