Question

The sides of a right angle angle triangle PQR are PQ=7cm,QR=25cm and angle p is 90 respectively.then find
TAN Q-TAN R

Answer 1

required answer is 527/168

Answer 2

Answer:

$tan \:Q - tan\:R=\frac{527}{168}$

Step-by-step explanation:

Given In ∆PQR , <P = 90°,

PQ = 7 cm, QR = 25 cm

/* By Pythagoras theorem:

PR² = QR² - PQ²

= 25²- 7²

= 625 - 49

= 576

PQ = 24

Now,

$tan \:Q - tan\:R\\=\frac{PR}{PQ}-\frac{PQ}{PR}\\=\frac{24}{7}-\frac{7}{24}\\=\frac{24^{2}-7^{2}}{168}\\=\frac{576-49}{168}\\=\frac{527}{168}$

Therefore,.

$tan \:Q - tan\:R=\frac{527}{168}$

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