Question

The sides of a right angle triangle PQR are PQ=7cm,PR=25cm and angle Q=90° respectively then find tanP-tanR

Answer 1

Answer:

Refer the attachment.

Hope it helps ,

Answer 2

Answer:

Given:

PQ = 7cm

PR = 25cm

<Q = 90°

∴ By Pythagoras theorem,

= (PR)² = (RQ)² + (QP)²

= (RQ) =

= RQ = $\sqrt{626-49}$  (∵ $\sqrt{25^2-7^2}$)

= RQ = √576 = √24² (√ and ² will get Cancelled)

⇒ RQ = 24cm