Question

The sides of a right angle triangle PQR are PQ =7cm; QR=25cm then find; tanQ-tanR

Answer 1

Answer:

In the ∆ PQR,

• PQ = 7 cm.
• QR = 25 cm.
• PR = ?
• tan Q - tan R = ?

By using ″ Pythagoras theorem ″ , we get PR

➡ (HYPOTENUSE)² = (SIDE)² + (SIDE)²

➡ (QR)² = (PQ)² + (PR)²

➡ (25)² = (7)² + (PR)²

➡ 625 = 49 + (PR)²

➡ (PR)² = 625 - 49

➡ (PR)² = 576

➡ (PR) = √576

➡ (PR) = 24

Now, we have all sides of triangle.

• PQ = 7 cm.
• PR = 24 cm.
• QP = 25 cm.

➡ tan Q = Opposite/Adjacent

➡ tan Q = PR/QR

➡ tan Q = 24/7

➡ tan P = Opposite/Adjacent

➡ tan R = PQ/PR

➡ tan R = 7/24

➡ tan Q - tan R

➡ 24/7 - 7/24

➡ 576 - 49/168

➡ 552/168

➡ 23/6

∴ The value of tan Q - tan R = 23/6

Step-by-step explanation:

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