Question

The sides of a right angled triangle are 4x-1, 4x, 4x+1. Find x.
please help me out!!​

Answer 1

Answer:

its simple apply the pythagorus theorem in the triangle.

Answer 2

Answer:

as the triangle is right angled

so,

perpendicular^2+base^2=hypotenuse^2

hupotenuse is the largest side of the right angle triangle.

(4x-1)^2+(4x)^2=(4x+1)^2

=> 16x^2-8x+1+16x^2=16x^2+8x+1

=> 32x^2-8x+1-16x^2-8x-1=0

=> 16x^2-16x=0

=> 16x(x-1)=0

=> 16x=0

=> x=0/16=0

=> x-1=0

=> x=1

so the sides are( 4.1-1) , 4.1 , (4.1+1)=3 , 4 , 5