Question

the sides of a right angled triangle are in AP. Show that they are in the ratio 3:4:5​

Answer 1

Answer:

Here, a is the first term of the AP and d is the common difference. Clearly, the largest side or the hypotenuse of the right angled triangle would be a+d. Hence, the sides a−d , a , a+d becomes 3d , 4d , 5di.e. they are in the ratio,3:4:5.

Step-by-step explanation:

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