Question

the sides of a right angled triangle are x-5,x+12,X+13 find the area of the triangle

Answer 1

Answer:

Considering the +ve value of x=> The right angled ∆ having sides as mentioned in question=> (x+8)²=(x+7)²+x² => x²+16x+64=x²+14x+49+x²=>x²-2x-15 =(x-5)(x+3)=0 => x=5. now (x+7) =5+7=12, => Area=(1/2)×5×12=30 sq units.

Step-by-step explanation:

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