The sides of a right-angled triangle are x, (x+2) and (2x-2). The hypotenuse is length(2x-2). Find the actual dimensions of the triangle.
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By Pythagoras theorem
x^2+x^2+4x+4=4(x^2-2x+1)
2x^2+4x+4=4x^2-8x+4
2x^2-12x=0
2x(x-6)=0
x=0 or x=6.
so dimensions are
6,8,10.
x^2+x^2+4x+4=4(x^2-2x+1)
2x^2+4x+4=4x^2-8x+4
2x^2-12x=0
2x(x-6)=0
x=0 or x=6.
so dimensions are
6,8,10.
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