The sides of a right angled triangle forming right angle are 5cm and 12cm Find the radius of the cirumcircle of the triangle.
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So the given right angled triangle is circumscribed in a circle
Now from the diagram u can see the angle formed at A is a right angle
That is Angle BAC=90°
but we know that a diameter subtends a right angle at any point on the circle
Hence BC is the diameter
But
BC^2=BA^2+AC^2
=5^2+12^2
=169
Taking square root
BC=13
OB is the radius here
But
OB=1/2 * BC
=1/2 * 13
=6.5cm
Hope it helps
:)
Now from the diagram u can see the angle formed at A is a right angle
That is Angle BAC=90°
but we know that a diameter subtends a right angle at any point on the circle
Hence BC is the diameter
But
BC^2=BA^2+AC^2
=5^2+12^2
=169
Taking square root
BC=13
OB is the radius here
But
OB=1/2 * BC
=1/2 * 13
=6.5cm
Hope it helps
:)
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