Question

The sides of a right angled triangle PQR are PQ=7cm , PR=25cm , and Q =90° respectively. Then find , tanP- tanR
​

Answer 1

Answer:

refer the attachment ,

In △ PQR using pythagoras theorem

$\implies$(PR) ² = (PQ) ² +(QR) ²

625-49=(QR) ²

(QR) ² =576

QR=24CM

now ,tan P = $\frac{7}{24}$

and tan R= $\frac{</strong><strong>2</strong><strong>4</strong><strong>}</strong><strong>{</strong><strong>7</strong><strong>}$

$\longrightarrow$ tanP-tanR= 7/24 − 24/7 = 168/

$\longrightarrow$$\frac{168}{576 - 49}$

$\longrightarrow$$\frac{168}{527}$

$\longrightarrow$168/576−49

Ans: = 168/527

Answer 2

Answer:

Given:

PQ = 7cm

PR = 25cm

<Q = 90°

∴ By Pythagoras theorem,

= (PR)² = (RQ)² + (QP)²

= (RQ) = $\sqrt{(PR)² - (QP)²}$

= RQ = $\sqrt{626-49}$  (∵ $\sqrt{25^2-7^2}$)

= RQ = √576 = √24² (√ and ² will get Cancelled)

⇒ RQ = 24cm