Question

the sides of a right triangle are 5cm,,12cmand13cm .then the area is​ Step - by - Step -

Answer 1

Answer:

Assume that ,

ABC be a Right triangle.

Where,

AB = 5 cm

BC = 12 cm

CA = 13 cm

Formula Method.

★ Area of right triangle = 1/2 × base × height

Here,

Base = AB = 5 cm

Height = BC = 12 cm

So, keep all values,

➡ Area of right triangle ABC = 1/2 × 5 × 12

➡ Area of right triangle ABC = 5 × 6

➡ Area of right triangle ABC = 30 cm²

_________________________

Using Heron's Formula

Let,

➡Semi perimeter (S) = (AB + BC + CA)/2

So,

➡ Semi perimeter (S) = (5+12+13)/2

➡ Semi perimeter (S) = 30/2

➡ Semi perimeter (S) = 15 cm

Heron's Formula,

★Area = √[S(S-AB)(S-BC)(S-CA)]

keep all above values

➡ Area = √[15(15-5)(15-12)(15-13)]

➡Area = √[15×10×3×2]

➡Area = √(900)

➡Area = 30 cm²

_________________________

Hence

Area of right triangle will be = 30cm²

________________

Answer 2

Answer:

Hypotenuse will be opposite to right angle which is 13 cm

The base and height will be 5 cm and 12 cm.

Area of triangle=

2

1

×

100

5

×

100

12

=

10000

30

=0.003 m

2

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