the sides of a right triangle are 5cm,,12cmand13cm .then the area is Step - by - Step - Explanation Assume that , ABC be a Right triangle. Where, AB = 5 cm BC = 12 cm CA = 13 cm Formula Method. ★ Area of right triangle = 1/2 × base × height Here, Base = AB = 5 cm Height = BC = 12 cm So, keep all values, ➡ Area of right triangle ABC = 1/2 × 5 × 12 ➡ Area of right triangle ABC = 5 × 6 ➡ Area of right triangle ABC = 30 cm² _________________________ Using Heron's Formula Let, ➡Semi perimeter (S) = (AB + BC + CA)/2 So, ➡ Semi perimeter (S) = (5+12+13)/2 ➡ Semi perimeter (S) = 30/2 ➡ Semi perimeter (S) = 15 cm Heron's Formula, ★Area = √[S(S-AB)(S-BC)(S-CA)] keep all above values ➡ Area = √[15(15-5)(15-12)(15-13)] ➡Area = √[15×10×3×2] ➡Area = √(900) ➡Area = 30 cm² _________________________ Hence Area of right triangle will be = 30cm² ________________hi
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Answer:
,
ABC be a Right triangle.
Where,
AB = 5 cm
BC = 12 cm
CA = 13 cm
Formula Method.
★ Area of right triangle = 1/2 × base × height
Here,
Base = AB = 5 cm
Height = BC = 12 cm
So, keep all values,
➡ Area of right triangle ABC = 1/2 × 5 × 12
➡ Area of right triangle ABC = 5 × 6
➡ Area of right triangle ABC = 30 cm²
_________________________
Using Heron's Formula
Let,
➡Semi perimeter (S) = (AB + BC + CA)/2
So,
➡ Semi perimeter (S) = (5+12+13)/2
➡ Semi perimeter (S) = 30/2
➡ Semi perimeter (S) = 15 cm
Heron's Formula,
★Area = √[S(S-AB)(S-BC)(S-CA)]
keep all above values
➡ Area = √[15(15-5)(15-12)(15-13)]
➡Area = √[15×10×3×2]
➡Area = √(900)
➡Area = 30 cm²
_________________________
Hence
Area of right triangle will be = 30cm²
________________
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