Question

the sides of a right triangle are 5cm,,12cmand13cm .then the area is​


Urgently

Answer 1

Explanation:

Explanation:

Answer:

Assume that ,

ABC be a Right triangle.

Where,

AB = 5 cm

BC = 12 cm

CA = 13 cm

Formula Method.

★ Area of right triangle = 1/2 × base × height

Here,

Base = AB = 5 cm

Height = BC = 12 cm

So, keep all values,

➡ Area of right triangle ABC = 1/2 × 5 × 12

➡ Area of right triangle ABC = 5 × 6

➡ Area of right triangle ABC = 30 cm²

_________________________

Using Heron's Formula

Let,

➡Semi perimeter (S) = (AB + BC + CA)/2

So,

➡ Semi perimeter (S) = (5+12+13)/2

➡ Semi perimeter (S) = 30/2

➡ Semi perimeter (S) = 15 cm

Heron's Formula,

★Area = √[S(S-AB)(S-BC)(S-CA)]

keep all above values

➡ Area = √[15(15-5)(15-12)(15-13)]

➡Area = √[15×10×3×2]

➡Area = √(900)

➡Area = 30 cm²

_________________________

Hence

Area of right triangle will be = 30cm²

________________

Answer 2

$We \: \: have, \\ s = \frac{a + b + c}{2} \\ \\ = \frac{5 + 12 + 13}{2} \\ \\ = \frac{30}{2} \\ \\ = 15 \: cm \\ \\ Now, \: Area(A) = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{15(15 - 5)(15 - 12)(15 - 13)} \\ \\ = \sqrt{15 \times 10 \times 3 \times 2} \\ \\ = \sqrt{900} \\ \\ = \sqrt{ {(30)}^{2} } \\ \\ = 30 \: {cm}^{2}$

I hope this helps.