Math, asked by rajdubey91250, 11 months ago

The sides of a right triangle are in the ratio of
3:4:5 and its perimeter is 12 cm. Find its area.

Answers

Answered by rajsingh24

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Let the nos. be: 3x, 4x and 5x .

So,

3x+4x+5x=120

x(3+4+5)=120

Now,

x = 120 ÷ (3+4+5)

x = 120 ÷ 12

x=10

So, from here as our value for x is 10 ,

We will multiply 10 by the ratio nos.

So,

3×10=30unit

4×10=40unit

5×10=50unit

Now we will use heron's formula for the area

That is :-

=√[s(s-a)(s-b)(s-c)] where s=1/2 of perimeter that is 1/2×120=60

So,

=√[60(60-30)(60-40)(60-50)]

=√[60×30×20×10]

=√[360000]

=600

So, 600 unit ^2 is the area of the triangle.

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