Question

the sides of a right triangles are x-3, x+1 and x+5 find the value of x​

Answer 1

Answer:

thanks for point in the form of a cone of radius 3 fecial hand leg wex under the balls being of same size as a d.in to the following quadratic equation do

Answer 2

Answer:

(x + 5)² = (x - 3)² + (x + 1)²

» x² + 25 + 10x = x² + 9 - 6x + x² + 2x + 1

» x² - 14x - 15 = 0

» x² - 15x + x - 15 = 0

» x (x - 15) + (x - 15) = 0

» (x - 15) (x + 1) = 0

» x = 15 or -1

Since, side can't be negative x = 15