The sides of a traingle are in the ratio 13:14:15 and it perimeter is 84 cm find the area of the traingle
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1
let sides be 13x , 14x and 15x
perimeter = sum of sides
84 = (13+14+15) x
84 = 42x
x =2
sides = 26 , 28 , 30
plz refer to attachment for area
perimeter = sum of sides
84 = (13+14+15) x
84 = 42x
x =2
sides = 26 , 28 , 30
plz refer to attachment for area
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Answered by
2
Let the No. be x
13x+14x+15x=84
42x=84
=x=84/42
=x=2
1st ratio=13x=13×2=26
2nd ratio=14x=14×2=28
3rd ratio= 15x=15×2=30
Now,
s= a+b+c/2
=26+28+30/2
=84/2
= 42
s-a=42-26=16
s-b=42-28=14
s-c=42-30=12
Area= √s(s-a)(s-b)(s-c)
=√42×16×14×12
=√2×3×7×2×2×2×2×2×7×2×2×3
=2×2×2×2×3×7
= 16×21
=336 cm^2 ans.
MARK BRAINLIEST..
13x+14x+15x=84
42x=84
=x=84/42
=x=2
1st ratio=13x=13×2=26
2nd ratio=14x=14×2=28
3rd ratio= 15x=15×2=30
Now,
s= a+b+c/2
=26+28+30/2
=84/2
= 42
s-a=42-26=16
s-b=42-28=14
s-c=42-30=12
Area= √s(s-a)(s-b)(s-c)
=√42×16×14×12
=√2×3×7×2×2×2×2×2×7×2×2×3
=2×2×2×2×3×7
= 16×21
=336 cm^2 ans.
MARK BRAINLIEST..
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