Question

The sides of a traingle are in the ratio of 12:17:25 and the perimeter is 540cm. find its area​

Answer 1

Answer:

The area is 9000 cm

Step-by-step explanation:

Answer 2

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Let the sides be 12x, 17x and 25x

Then the perimeter will be:-

12x + 17x + 25x = 540

54x = 540

x = $\frac{540}{54}$

x = 10

Therefore the sides are:-

12x = 12 × 10 = 120cm

17x = 17 × 10 = 170cm

25x = 25 × 10 = 250cm

Area = $\sqrt{s(s-a)(s-b)(s-c)}$

where,

s = semi-perimeter

a = length of side a

b = length of side b

c = length of side c

Here,

s = $\frac{540}{2}$ = 270

a = 120

b = 170

c = 250

Area = $\sqrt{s(s-a)(s-b)(s-c)}$

Area = $\sqrt{270(270-120)(270-170)(270-250)}$

Area = $\sqrt{270(150)(100)(20)}= \sqrt{81000000}$

Area = 9000cm²