The sides of a triangle ABC are produced in order to form
the exterior angles 1, 2, 3. Show that ∠1 +∠2 + ∠3 = 360°.
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ABC + ∠CBF = 180° [Linear pair]………..(i)
∠ACB + ∠ACD = 180° [Linear pair]……(ii)
∠BAC + ∠BAE = 180° [Linear pair]…….(iii)
Byadding(i), (ii) and (iii)
∠ABC + ∠CBF + ∠ACB + ∠ACD+ ∠BAC + ∠BAE = 180 + 180 + 180
∠ABC + ∠ACB + ∠BAC + ∠CBF + ∠ACD + ∠BAE = 540° 180° + ∠CBF + ∠ACD + ∠BAE = 540°
[Sum of the angles of a triangle 180°]
∠CBF + ∠ACD + ∠BAE = 360°Read more on
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