Question

The sides of a triangle are 100m, 120m, and 140m. Find its area.​

Answer 1

Answer:

The area of the triangle is 5880cm².

Step-by-step Explanation:

First we need to find out the side,

$\dfrac{\sf{side \: a + side \: b + side \: c}}{2}$

By putting the values,

$\longrightarrow \dfrac{100+120+140}{2}$

$\longrightarrow \dfrac{360}{2}$

= 180

Now, let's find the area of triangle

Area of triangle = $\sf{\sqrt{s(s-a)(s-b)(s-c)}}$

Therefore, by putting the values

$\longrightarrow \sf{ \sqrt{180(180-100)(180-120)(180-140)}}$

$\longrightarrow \sf{ \sqrt{180(80)(60)(40)}}$

$\longrightarrow \sf{ \sqrt{180 \times 80 \times 60 \times 40}}$

$\longrightarrow \sf{\sqrt{5460000}}$

$\longrightarrow \sf{2400 \sqrt{6}}$

$\longrightarrow \sf{ 2400 \times 2.45}$

$\longrightarrow \sf{ 5880}$

Therefore, area of triangle is $\sf{{5880cm}^{2}}$

Answer 2

Answer:

Answer:

The area of the triangle is 5880cm².

Step-by-step Explanation:

First we need to find out the side,

\dfrac{\sf{side \: a + side \: b + side \: c}}{2}

2

sidea+sideb+sidec

By putting the values,

\longrightarrow \dfrac{100+120+140}{2}⟶

2

100+120+140

\longrightarrow \dfrac{360}{2}⟶

2

360

= 180

Now, let's find the area of triangle

Area of triangle = \sf{\sqrt{s(s-a)(s-b)(s-c)}}

s(s−a)(s−b)(s−c)

Therefore, by putting the values

\longrightarrow \sf{ \sqrt{180(180-100)(180-120)(180-140)}}⟶

180(180−100)(180−120)(180−140)

\longrightarrow \sf{ \sqrt{180(80)(60)(40)}}⟶

180(80)(60)(40)

\longrightarrow \sf{ \sqrt{180 \times 80 \times 60 \times 40}}⟶

180×80×60×40

\longrightarrow \sf{\sqrt{5460000}}⟶

5460000

\longrightarrow \sf{2400 \sqrt{6}}⟶2400

6

\longrightarrow \sf{ 2400 \times 2.45}⟶2400×2.45

\longrightarrow \sf{ 5880}⟶5880

Therefore, area of triangle is \sf{{5880cm}^{2}}5880cm

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