Question

the sides of a triangle are 10cm 24 cm and 26 cm find the length of perpendicular drawn from vertex to side of 24 cm

Answer 1

Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝

Solution:-)The given sides of triangle ABC are a = 10cm, b = 24cm and c = 26cm.

Semi-perimeter of triangle, S = 10+24+26/2=60/2=30

Area of Triangle ABC=√30(30-10)(30-24)(30-26)

=)120 cm²

Now,,,

Area of Triangle=
$1 \div 2 \times base \times height$

120=1/2*24×h
H=120/12
H=10

that's all

@Sujeet

Answer 2

Step-by-step explanation:

The given sides of triangle ABC are a = 10cm, b = 24cm and c = 26cm.

Semi-perimeter of triangle, S = 10+24+26/2=60/2=30

Area of Triangle ABC=√30(30-10)(30-24)(30-26)

=)120 cm²

Now,,,

Area of Triangle=

1 \div 2 \times base \times height1÷2×base×height

120=1/2*24×h