Question

The sides of a triangle are 11m , 60m, 61m . The altitude of smallest side is (a)11cm (b)66cm (c)50cm (d)60cm

Answer 1

Answer:

Option (d) is correct.

Step-by-step explanation:

Given the sides of a triangle are 11m , 60m, 61m. we have to find the altitude of smallest side of triangle.

In figure, the smallest side is BC which is 11m which means we have to find the length of AD.

$Semiperimeter,s=\frac{a+b+c}{2}=\frac{60+61+11}{2}=\frac{132}{2}=66cm$

By heron's formula,

$\text{Area of ABC}$=$\sqrt{s(s-a)(s-b)(s-c)}$

$\frac{1}{2}baseBC\times heightAD=\sqrt{66(66-60)(66-61)(66-11)}$

⇒ $\frac{1}{2}\times 11\times AD=\sqrt{66(6)(5)(55)}$

⇒ $AD=\frac{2\times 11\times 6\times 5}{11}$

⇒ AD=60 cm

hence, option (d) is correct

Answer 2

Answer:

60 cm

Step-by-step explanation:

area = 30×11 = 330

altitude => area = 1/2× 11× altitude

330= 1/2×11× altitude

=>altitude=( 330×2)/11= 30×2 = 60 will be the answer