The sides of a triangle are 11m 60m and 61m. Find the altitude to the largest side.
Class 9th
Answers
Answered by
0
Answer:
The area of a triangle having sides a,b,c and S as semi-perimeter is given by
A=
S(S−a)(S−b)(S−c)
S=
2
a+b+c
=
2
11+60+61
=
7
132
=66cm
We need to find the altitude to smallest side
A=
66(66−11)(66−60)(66−61)
⇒A=
66,55,6.5
⇒A=
106900
⇒A=330m
2
The area of a triangle having base AC and height P/S given by
Area (A) =
2
1
=
2
1
(Base × Height)
Area (A)=
2
1
(AC×P)
We need to find the height P. Here the smaller side is 11 m.
AC= 11 m
330=
2
1
.(11×p)
330×2=11×p
660=11×p
∴p=660/11
p=60 m.
∴ So, the answer is D. 60 m
Answered by
0
Answer:
There is no solution for hb (violates hb > 0). Please modify the input values
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