Question

The sides of a triangle are 11m 60m and 61m. Find the altitude to the largest side.
Class 9th ​

Answer 1

Answer:

The area of a triangle having sides a,b,c and S as semi-perimeter is given by

A=

S(S−a)(S−b)(S−c)

S=

2

a+b+c

=

2

11+60+61

=

7

132

=66cm

We need to find the altitude to smallest side

A=

66(66−11)(66−60)(66−61)

⇒A=

66,55,6.5

⇒A=

106900

⇒A=330m

2

The area of a triangle having base AC and height P/S given by

Area (A) =

2

1

=

2

1

(Base × Height)

Area (A)=

2

1

(AC×P)

We need to find the height P. Here the smaller side is 11 m.

AC= 11 m

330=

2

1

.(11×p)

330×2=11×p

660=11×p

∴p=660/11

p=60 m.

∴ So, the answer is D. 60 m

Answer 2

Answer:

$Triangle$

$Solve for </p><p></p><p>height</p><p></p><p></p><p>$

$h</p><p></p><p>b</p><p></p><p>=</p><p></p><p>?</p><p></p><p>m</p><p></p><p>$

$a</p><p></p><p>Side \: 11m</p><p></p><p></p><p>$

$b \: </p><p></p><p>Base \: </p><p></p><p> \: 60 \: m</p><p></p><p>$

$c \: </p><p></p><p>Side \: </p><p></p><p>61 \: m</p><p>$

There is no solution for hb (violates hb > 0). Please modify the input values