Question

The sides of a triangle are 12cm ,16cm and 20cm. Its area is ​

Answer 1

Answer:

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Answer 2

Question :- The sides of a triangle are 12cm, 16cm and 20cm . find its area ?

Solution :-

we have given that, sides of a triangle are 12cm, 16cm and 20cm.

So,

→ Perimeter of ∆ = (12 + 16 + 20) = 48 cm.

→ Semi - Perimeter = 48/2 = 24 cm.

then,

→ Area of ∆ = √[s*(s-a)*(s-b)*(s-c) , where s is semi - perimeter and a , b and c are length of sides of ∆ .

Putting values we get,

→ Area of ∆ = √[24 * (24 - 12) * (24 - 16) * (24 - 20)]

→ Area of ∆ = √(24 * 12 * 8 * 4)

→ Area of ∆ = √(2 * 12 * 12 * 2 * 4 * 4)

→ Area of ∆ = √(2² * 12² * 4²)

→ Area of ∆ = 2 * 12 * 4

→ Area of ∆ = 96 cm².

Hence, Area of triangle will be 96 cm².

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