the sides of a triangle are 15 cm, 20 cm and 25 cm. find the perpendicular distance of its greatest side from its opposite vertex
Hey guyzzz please help me i m in very difficult stage tommorow is my math exam so please
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find area by heron's formula first
a=15cm b=20cm c=25cm
s=(a+b+c)/2=(15+20+25)/2=30
area, A=√[s(s-a)(s-b)(s-c)
A=√30(30-15)(30-20)(30-25)
A=√ 30*15*10*5=150cm²
also , area of triangle, A= (1/2)*base*height
c=25 cm is greatest side
let, corresponding height be h
A= (1/2)*25*h
150=(1/2)*25*h
300=25h
h=12cm
a=15cm b=20cm c=25cm
s=(a+b+c)/2=(15+20+25)/2=30
area, A=√[s(s-a)(s-b)(s-c)
A=√30(30-15)(30-20)(30-25)
A=√ 30*15*10*5=150cm²
also , area of triangle, A= (1/2)*base*height
c=25 cm is greatest side
let, corresponding height be h
A= (1/2)*25*h
150=(1/2)*25*h
300=25h
h=12cm
mah2:
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yes dear it is 100% correct
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