Question

the sides of a triangle are 16cm 12cm and 20cm find it's area

Answer 1

hi frnd

here is your answer

in the attachment

i hope it helps you

Answer 2

Question:

The sides of a triangle are 16 cm 12 cm and 20 cm find it's area.

Given:

The sides of a triangle :-

1. 16 cm
2. 12 cm
3. 20 cm

To Find:

• Area of Triangle.

Solution:

Area of triangle =

$\sqrt{s(s - a)(s - b)(s - c)}$

First, we need the value of "s"

So,

$s = \frac{a + b + c}{2}$

$\implies \frac{16 + 12 + 20}{2}$

$\implies \frac{ \cancel48}{ \cancel2}$

$\implies 24$

Area of ∆ = $\sqrt{24(24 - 16)(24 - 12)(24 - 20)}$

$\implies \sqrt{24(8)(12)(4)}$

$\implies \sqrt{24 \times 8 \times 12 \times 4}$

$\implies \sqrt{2 \times 2 \times 2 \times 3 \times 2 \times 2 \times 2 \times 2 \times 3 \times 2 \times 2}$

$\implies 2 \times 2 \times 2 \times 2 \times 2 \times 3$

$\implies {96 \: cm}^{2}$

Hence,

The area of a triangle is ${96 \: cm}^{2}$