Question

The sides of a triangle are 20 cm, 16 cm,and 12 cm. Find the following:
a.The area of the triangle
b. The length of the perpendicular on the shortest side of the triangle.​

Answer 1

Answer:

Area of triangle with sides a, b,and c and s =

2

a+b+c

is

s(s−a)(s−b)(s−c)

.

For triangle with sides 16 cm, 12 cm and 20 cm, s=

2

16+12+20

=24cm

Area of the triangle with sides 16 cm, 12 cm and 20 cm =

24(24−16)(24−12)(24−20)

=

24×8×12×4

=

8×3×8×4×3×4

=8×3×4=96cm

2

Area of triangle can also be calculated using the formula

2

1

×base×height

Let the height for base 12cm, be h.

So, area =

2

1

×12×h=96cm

2

=>h=16cm