Question

the sides of a triangle are 22cm,20cm, 18cm and find its area

Answer 1

Heya ^_^

Using Heron's formula --

Area of triangle = √s(s-a) (s-b) (s-c)

Here s = semi -perimeter = {22+18+20}/2= 30

a = 22
b = 20
C = 18

Area = √30 (30-22)(30-20)(30-18)

Area = √30(8)(10)(12)

Area = √(10 × 3 )×( 2 ×4) × 10 × 3 ×4

Area = 10× 3×4 √2

Area = 120√2

Answer 2

a = 22 cm

b = 20 cm

c = 18 cm

S = ( 22 + 20 +18)/2

= (60 /2)

= 30

(s-a) = (30 - 22) = 8

(s-b) = (30 - 20) = 10

(s-c) = (30 - 18) = 12

$area \: = \sqrt{s(s - a)(s -b)( s- c } \\ \\ = \sqrt{30 \times 8 \times 10 \times 12} \\ \\ = \sqrt{5 \times 3 \times 2 \times 2 \times 2 \times 2 \times 5 \times 2 \times 3 \times 2 \times 2 } \\ \\ = 5 \times 3 \times 2 \times 2 \times 2 \times sqrt[2] \\ \\ = 120 sqrt [2] \: c {m}^{2}$