Question

The sides of a triangle are 22cm 20cm and 18 cm find its area

Answer 1

Answer:

$\boxed{\bold{Area = 120 cm}}$

Step-by-step explanation:

Given that,

Length of side a = 22 cm

Length of side b = 20 cm

Length of side c = 18 cm

To find,

It's area = ?

By using Heron's formula,

Area = $\sqrt{s(s - a)(s - b)(s - c)}$

Where, s = $\frac{a+b+c}{2}$ (or) semi - perimeter (or) half of the perimeter.

s = $\frac{(22 + 20 + 18)cm}{2}$

s = $\frac{60}{2}$

s = $\frac{\cancel{60}}{\cancel{2}}$

s = 30 cm

By substituting the values of a, b and c,

Area = $\sqrt{s(s - a)(s - b)(s - c)}$

Area = $\sqrt{30(30-22)(30-20)(30-18)}$

Area = $\sqrt{30(8)(10)(12)}$

Area = $\sqrt{2 \times 3 \times 5(2 \times 2 \times 2)(2 \times 5)(2 \times 2 \times 3)}$

Area = $2 \times 3 \times 5 \times 2 \times 2$

$\boxed{\bold{Area = 120 cm}}$

Answer 2

$\huge{\underline{\red{\mathcal{Hey, Mate..!}}}}$      

$\huge{\orange{AnSwEr:-}}$

See the attachmentß.....✌☺