Question

The sides of a triangle are 24 cm, 31 cm and 43 cm. The length of the longest altitude of the triangle is

Answer 1

Step-by-step explanation:

$Area = \sqrt{} ( s \ - \ a) (s - b)(s﹣c) \\ s = \frac{a + b + c}{2} \\ a =24 \\ b = 31\\ c = 43 \\ finding \: semi perimeter \\ s = \frac{24 + 31 + 43}{2} \\ s = \frac{98}{2} \\ s = 49 \\ put \: value \: of \: s \: \\ in \: the \: formula \\ Area= \sqrt s(s - a)(s - b)(s﹣c) \\ Ar= \sqrt 49(49 -24)(49 - 31)(49 - 43) \\ Ar= \sqrt{} 49 \times 25 \times 18 \times 6 \\ ar= \sqrt{132300} \\ ar = 363.73 \: (approx.)</p><p>$