Question

the sides of a triangle are 25 cm 39 cm and 56 cm . Find (i) area (ii) the lengof the perpendicular drawn from the opposite vertex ro the side of 25 cm

Answer 1

$\textbf{\huge{ANSWER:}}$

To find the area, we can use the Heron's formula.

Semi perimeter = $\frac{25 + 39 + 56}{2}$

=》 60 cm

Now, put it in the Heron's Formula, which is:

$\sqrt{60(60 - 25)(60 - 39)(60 - 56)} \\ \\ = > \sqrt{60(35)(21)(4)} \\ \\ = > 2\times 5 \times 6 \times 7 \\ \\ = > 420 \: {cm}^{2}$

Now, we can find the length of the altitude by putting the formula:

Area = $\frac{1}{2} \times Base \times Height$

=》 420 = $\frac{1}{2} \times 25 \times Height$

=》 $Height = \frac{420 \times 2}{25}$

=》 $\textbf{Height = 33.6 cm}$

Hope it Helps!! :)

Answer 2

Step-by-step explanation:

:.s = 39+56+25/2

=120/2

=60.

$\sqrt{s(s-39)(s-56)(s-25)}$

$\sqrt{60(60-39)(60-56)(60-25)}$

$\sqrt{60×(21)(4)(35)}$

=$\sqrt{3×2×5×2×2×2×5×7×3×7}$

=3×2×2×5×7

=12×35

=420cm²

H=2×a/b

=2×420/25

=168/5

=33.6ans✔

Regards..❤