Question

the sides of a triangle are 25 cm,39cm,and 56cm,find the altitude of longest side.
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Answer 1

Answer:

Let a=25 m, b=39 m, c=56 m

We have, semi-perimeter, s=

2

a+b+c

s=

2

25+39+56

s=

2

120

=60 m

Area of triangle=

s(s−a)(s−b)(s−c)

=

60(60−25)(60−39)(60−56)

=

60(35)(21)(4)

=

176400

=420 m

2

Area of triangle=

2

1

bh, where b-base and h-height

base=greatestside=56 m

420=

2

1

(56)h

h=

56

840

h=15 m

Step-by-step explanation:

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Answer 2

Please refer to the above attachment

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