Question

The sides of a triangle are 25cm,17cm and 12cm.The length of the altitude on the longest side is equal to

Answer 1

first find area of triangle =( 25+17+12)/2
s=27cm
root(27×2×10×15)
area = 90cm^2
now area =1/2 ×b×h
base take as longest side =25
1/2×25×h=90
h=90×2/25
h=36/5cm

Answer 2

Dear Student,

◆ Answer -

h = 7.2 cm

● Explaination -

Semiperimeter is given by -

s = (a + b + c) / 2

s = (25 + 17 + 12) / 2

s = 27 cm

Area of triangle is calculated by -

Area of triangle = √[s (s-a) (s-b) (s-c)]

Area of triangle = √[27 (27-25) (27-17) (27-12)]

Area of triangle = 90 cm^2

Let h be altitude of longest side.

Area of triangle = 1/2 × b × h

90 = 1/2 × 25 × h

h = 90 / 12.5

h = 7.2 cm

Hence, altitude of longest side is 7.2 cm.

Thanks dear. Hope this helps you...