Question

the sides of a triangle are 26cm,28cm,and 30cm,. find the altitude corresponding to the base 30cm.​

Answer 1

Answer:

the three sides of atriangle are 26cm ,28 cm and 30cm. ... let the height of the triangle corresponding to the longest side be h cm. therefore. thus the height of the triangle corresponding to the longest side is

Step-by-step explanation:

hope it will help u to

Answer 2

Answer:

the altitude of the corresponding to the base 30cm is 22.4cm

Step-by-step explanation:

first find the area of triangle$s=\frac{26+28+30}{2}=\frac{84}{2}=42 cm$

By heron's formula

$Area=\sqrt{s(s-a)(s-b)(s-c)}$

where s is semiperimeter i.e

$s=\frac{a+b+c}{2}$

Sides of triangle 26 cm, 28 cm and 30 cm.

$s=\frac{26+28+30}{2}=\frac{84}{2}=42 cmArea=\sqrt{42(42-26)(42-28)(42-30)} =\sqrt{42\times 16\times 14\times 12}=\sqrt{112896}=336 cm^2\text{The of triangle is }336 cm^2$

so the area is 336 cm2

for finding the altitude:

area = 1/2 hb

336=1/2*h*30

336/15=h

h=22.4cm

So the altitude of the corresponding to the base 30cm is 22.4cm

Hope it helps u....

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