Question

the sides of a triangle are 28cm, 36cm and 48cm, find the lengths of line -segments into which the smallest side is divided by the bisector of the angle opposite to it.​

Answer 1

Step-by-step explanation:

Area of triangle =√s(s-a)(s-b)(s-c) (s=semipermeter)

s=(a+b+c)/2

s=(28+36+48cm)/2

s=112/2

s=56

Area of triangle =√56(56-28)(56-36)(56-48)

Area of triangle =√56×28×20×8

Area of triangle =√250880

Area of triangle =500.879

Area of triangle =500.88cm^2

In second part the question ask about the length of altitude which is on the smallest side of length 28cm

Therefore, Area of triangle =1/2×base×height

500.88=1/2×28×height

500.88=14×height

500.88/14=height

35.77cm=height

or

Area of triangle =1/2×base×height

500.879=1/2×28×height

500.879=14×height

500.879/14=height

35.77cm=height

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