the sides of a triangle are 3 4 5 respectively. find the perpendicular distance from the vertex opposite to the side 3cm
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Now we have,
ΔABC=ΔPBC+ΔPAB+ΔPAC
=12PD.AC+12PE.AB+12PF.AC
=L2(PD+PE+PF)
=L2(3+4+5)=6L cm2.
Now, since ΔABC is an equilateral triangle with side L , its area is given by the formula 3√4L2 .
So 3√4L2=6L .
⟹L=83–√
Hence the area of the given equilateral triangle is 48 3–√ cm2 .
Hope it helps
Peace!!
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