Math, asked by vivek1234570, 7 months ago

The sides of a triangle are 3 cm, 5 cm and 6 cm. What is its area?
1 point
2√3cm2
2√14cm2
5√12cm2
2√5cm2​

Answers

Answered by Anonymous
6

Answer:

a = 3 cm

b = 5 cm

c = 6 cm

s =  \frac{a + b + c}{2}

s =  \frac{3 + 5 + 6}{2}

s =  \frac{14}{2} \:  cm

s = 7

area \:  \: of \: \:  triangle =  \sqrt{s(s - a)(s - b)(s - c)}

 =  \sqrt{7(7 - 3)(7 - 5)(7 - 6)}   \: {cm}^{2}

 =  \sqrt{7  \times  4  \times  2  \times 1}  \:  {cm}^{2}

 =  \sqrt{7  \times  (2  \times 2)  \times  2  \times 1}  \:  {cm}^{2}

 = 2  \sqrt{7  \times 2  \times  1}  \:  {cm}^{2}

 = 2 \sqrt{14}  \:  {cm}^{2}

 => 2 \sqrt{14}

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