Question

The sides of a triangle are 3 cm, 5 cm and 6 cm. What is its area?

a)2$2\sqrt{3}$ sq cm
b)$2\sqrt{14}$ sq cm
c)$5\sqrt{12}$ sq cm
d) $2\sqrt{5}$ sq cm

Answer 1

hey mate here is ur answer

a=3,b=5,c=6

Area of triangle = root(s(s-a)(s-b)(s-c))

s=7

=root(7×4×2)

=2root14

hence b) is ✔✔✔.

hope it helps.

☆☆☆

Answer 2

Answer:

B

Step-by-step explanation:

Given,

sides of triangle are 3,5 and 6 cms

Area of a triangle= √s(s-a)(s-b)(s-c) where s=a+b+C/2

Here,

a=3cms

b=5cms

c=6cms

now,

s= a+b+c/2

=3+5+6/2

=14/2

=7

Let,

Area of triangle=√s(s-a)(s-b)(s-c)

=√7(7-3)(7-5)(7-6)

=√7(4)(2)(1)

=√7(8)

=√56

= √2^2× √2×√7

=2×√14

Therefore,

Area of the triangle=2√14

hope it helps