Math, asked by JashmeenChahal, 10 days ago

The sides of a triangle are 35 cm, 54 cm and 61 cm.
The length of its longest altitude is
7​

Answers

Answered by WintaeBearTATA
11

Answer:

a = 35, b = 54, c = 61

s = (a + b + c)/2

⇒ s = (35 + 54 + 61)/2 = 150/2 = 75.

Area(Δ) = √s(s-a)(s-b)(s-c)

⇒ Area(Δ) = √75(75 - 35)(75 - 54)(75 - 61)

⇒ Area(Δ) = √75 × 40 × 21 × 14

⇒ Area(Δ) = 420√5 cm2

Area(Δ) = 1/2 × Base × Altitude

As the area of the triangle is fixed, for the longest altitude we need smallest base.

So, the length of base = 35cm

Area(Δ) = 1/2 × Base × Altitude

⇒ 420√5 = 1/2 × 35 × Altitude

⇒ 24√5 = Altitude

Answered by gaurianushka987
4

Step-by-step explanation:

here is your answer

hope it will help you a lot

Attachments:
Similar questions