The sides of a triangle are 35 cm, 54 cm and 61 cm.
The length of its longest altitude is
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Answer:
a = 35, b = 54, c = 61
s = (a + b + c)/2
⇒ s = (35 + 54 + 61)/2 = 150/2 = 75.
Area(Δ) = √s(s-a)(s-b)(s-c)
⇒ Area(Δ) = √75(75 - 35)(75 - 54)(75 - 61)
⇒ Area(Δ) = √75 × 40 × 21 × 14
⇒ Area(Δ) = 420√5 cm2
Area(Δ) = 1/2 × Base × Altitude
As the area of the triangle is fixed, for the longest altitude we need smallest base.
So, the length of base = 35cm
Area(Δ) = 1/2 × Base × Altitude
⇒ 420√5 = 1/2 × 35 × Altitude
⇒ 24√5 = Altitude
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