Question

the sides of a triangle are 3x + 7,4x,-3 and 5 x + 3 find the sides of triangle if its perimeter is 55 unites

Answer 1

sum of all sides of triangle = perimeter of triangle...
3x+7+4x-3+5x+3=55
12x+7=55
12x=48
x=4 unit

first side is 3(4)+7=19
second side. is 4(4)-3=13
third side is 5(4)+3=23.....

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Answer 2

The sides of triangle can be found by using the formula
the perimeter of the triangle is equal to sum of the three sides
perimeter of the is given that 55
and sides of the triangle is given the
first side is 3x+7
second side is 4x-3
third side is 5x+3
perimeter of the triangle is equal to
3x+7+4x-3+5x+3=55
12x+7=55
12x=55-7
12x=48
X=48÷12
X=4
then
first side is 3x+7=3(4)+7=19
second side is 4x-3=4(4)-3=13
third side is 5x+3=5(4)+3=23


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