Question

the sides of a triangle are 4(x+y/3), 3x+2y and 2(x+3)+1/4(3y-1). find the length of the sides if the triangle is equilateral

Answer 1

Answer:

3+12=15units

Step-by-step explanation:

x+3y=3x+2y−2=4x+  

2

1

​  

y+1

Fromthefirsttwo,weget

x+3y=3x+2y−2

So

y=2x−2−>eqn1

Subvalueofyweget

x+3y=7x−6

and

4x+1/2y+1=4x+x−1+1=5x

Sincebothareequal

7x−6=5x

Sox=3

Subx=3ineqn1

y=4

Sovalueofasideisx+3y

=3+12=15units

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