The sides of a triangle are 42cm,34cm and 20cm.Calculate its area and the length of the height on the longest side.
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Answered by
293
s = semiperimeter = (42+34+20)/2 = 48 cm
a = 42 cm b = 34 cm c = 20 cm
Area = √[ s (s-a) (s-b) (s-c) ]
= √[ 48 * 6 * 14 * 28 ] cm² = 336 cm²
Altitude on the base of 42 cm = h
336 = 1/2 * 42 * h
h = 16 cm
a = 42 cm b = 34 cm c = 20 cm
Area = √[ s (s-a) (s-b) (s-c) ]
= √[ 48 * 6 * 14 * 28 ] cm² = 336 cm²
Altitude on the base of 42 cm = h
336 = 1/2 * 42 * h
h = 16 cm
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