Question

The sides of a triangle are 42cm,34cm, and 20cm. Calculate its area and the length of the height on the longest side

Answer 1

Answer:

Step-by-step explanation:

S = semiperimeter = (42+34+20)/2 = 48 cm

a = 42 cm    b = 34 cm    c = 20 cm

Area = √[ s (s-a) (s-b) (s-c) ]  

        = √[ 48 * 6 * 14 * 28 ]   cm²  = 336 cm²

Altitude on the base of 42 cm = h

       336 = 1/2 * 42 * h

       h = 16 cm

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Answer 2

Answer:

h =16 cm

Step-by-step explanation:

side A= 42cm

side B=34 cm

side C= 20 cm

s= 42+34+20/2

s=48

√48(48-42)(48-34)(48-20) -------> √s(s-a)(s-b)(s-c)__ ---> formula

=3*7*2*2*2*2

=336 cm²

Area= 1/2*b*h

336=1/2*42*h

336=21*h

h=336/21

h=16 cm