Question

The sides of a triangle are 45cm, 39cm, and 42 cm, find its semiperimeter​

Answer 1

Sides of a triangle are 45 cm, 39 cm and 42 cm. Here, a = 45cm, b = 39cm, c = 42cm Semi perimeter of triangle = s = (1/2) (a + b + c) = (1/2) (45 + 39 + 42) = 126/2 = 63 Area of a triangle ∴ The area of the triangle is 756 sq.

Answer 2

Step-by-step explanation:

Hey

a = 42 cm

b = 39cm

c = 45cm .

So ,

s = a + b + c / 2

s = 42 + 39 + 45 / 2

s = 126 / 2

s = 63 .

Now ,

area = \sqrt{s(s - a)(s - b)(s - c)}area=

s(s−a)(s−b)(s−c)

= \sqrt{63(63 - 42)(63 - 39)(63 - 45)}=

63(63−42)(63−39)(63−45)

= \sqrt{63 \times 21 \times 24 \times 18}=

63×21×24×18

= \sqrt{9 \times 7 \times 7 \times 3 \times 6 \times 4 \times 6 \times 3}=

9×7×7×3×6×4×6×3

= 3 \times 7 \times 3 \times 6 \times 2=3×7×3×6×2

= 108 \times 7=108×7

= 756=756

So , area = 756 cm²