Question

the sides of a triangle are 5,12and 13 cm find the lenght of it altitude to the longest side

pls help fast ​

Answer 1

Given :-

Sides of triangle = 13 cm, 5 cm and 12 cm

To Find :-

The longest side as base

Formula to be used :-

Area of triangle = √[s(s-a)(s-b)(s-c)]

Solution :-

Using Heron's Formula, we get

S = (a + b + c)/2

S = 5 + 12 + 13/2

S = 30/2

S = 15

Area of triangle = √[s(s - a)(s - b)(s - c)]

Area of triangle = √[15 (1 - 5) (15 - 12) (15 - 13)

Area of triangle = √[15 (10) (3) (2)

Area of triangle = √[ 900]

Area of triangle = √[30 × 30]

Area of triangle = 30 cm²

Now, we will find the attitude

Area of triangle = 1/2 × base × altitude

30 × 2  = 13 ×  altitude

60 / 13 = altitude

4.6 cm = altitude

Hence, the altitude corresponding to the longest side is 4.6 cm.

mark brainlist and follow me

Answer 2

Step-by-step explanation:

this is your solution Do it