Question

The sides of a triangle are 5½cm.7¾cm.and 9⅔cm. Find its perimeter

Answer 1

Answer:

Perimeter = 68/3 = 22whole 2/3

Step-by-step explanation:

5 1/2 = 11/2

7 3/4 = 31/4

9 2/3 = 29/3

Adding them by taking L.C.M.

66+ 93+ 113 /12

272/12

68/3

Answer 2

$\huge\bigstar\fcolorbox{red}{aqua}{\tt\pink{ANSWER}}\bigstar$

Perimeter = Sum of all sides

P = (5½ + 7¾ + 9⅔) cm

$=(5 \times \frac{1}{2} + 7 \times \frac{3}{4} + 9 \times \frac{2}{3} )cm$

$= ( \frac{11}{2} + \frac{31}{4} + \frac{29}{3} )cm$

LCM of 2 , 4 and 3 is 12

$={ { \frac{(11 \times 6) + (31 \times 3) + (29 \times 4)}{12} }}cm$

$= \frac{(66 + 93 + 116)}{12} cm$

$= \frac{275}{12} cm$

$= 22 \times \frac{11}{12} cm$

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